海康威视校园招聘笔试题

本文核心词:海康威视校招。

  1、10、10、4、4四个数,怎么算出24点?

  (10*10-4)/4=24

  2、下列表达式在32位机器编译环境下的值()

  class A

  {

  };

  class B

  {

  public:

  B();

  virtual ~B();

  };

  class C

  {

  private:

  #pragma pack(4)

  int i;

  short j;

  float k;

  char l[64];

  long m;

  char *p;

  #pragma pack()

  };

  class D

  {

  private:

  #pragma pack(1)

  int i;

  short j;

  float k;

  char l[64];

  long m;

  char *p;

  #pragma pack()

  };

  int main(void)

  {

  printf(“%d\n”,sizeof(A));

  printf(“%d\n”,sizeof(B));

  printf(“%d\n”,sizeof(C));

  printf(“%d\n”,sizeof(D));

  return 0;

  }

  class A

  {

  };

  class B

  {

  public:

  B();

  virtual ~B();

  };

  class C

  {

  private:

  #pragma pack(4)

  int i;

  short j;

  float k;

  char l[64];

  long m;

  char *p;

  #pragma pack()

  };

  class D

  {

  private:

  #pragma pack(1)

  int i;

  short j;

  float k;

  char l[64];

  long m;

  char *p;

  #pragma pack()

  };

  int main(void)

  {

  printf(“%d\n”,sizeof(A));

  printf(“%d\n”,sizeof(B));

  printf(“%d\n”,sizeof(C));

  printf(“%d\n”,sizeof(D));

  return 0;

  }A、1、4、84、82 B、4、4、82、84 C、4、4、84、82 D、1、4、82、82

  3、以下程序在32位机器下运行的结果是()

  #pragma pack(4)

  struct info_t

  {

  unsigned char version;

  unsigned char padding;

  unsigned char extension;

  unsigned char count;

  unsigned char marker;

  unsigned char payload;

  unsigned short sequence;

  unsigned int timestamp;

  unsigned int ssrc;

  };

  union info_u

  {

  unsigned char version;

  unsigned char padding;

  unsigned char extension;

  unsigned char count;

  unsigned char marker;

  unsigned char payload;

  unsigned short sequence;

  unsigned int timestamp;

  unsigned int ssrc;

  };

  #pragma pack()

  int main(void)

  {

  printf(“%d\n”,sizeof(info_t));

  printf(“%d\n”,sizeof(info_u));

  return 0;

  }

  #pragma pack(4)

  struct info_t

  {

  unsigned char version;

  unsigned char padding;

  unsigned char extension;

  unsigned char count;

  unsigned char marker;

  unsigned char payload;

  unsigned short sequence;

  unsigned int timestamp;

  unsigned int ssrc;

  };

  union info_u

  {

  unsigned char version;

  unsigned char padding;

  unsigned char extension;

  unsigned char count;

  unsigned char marker;

  unsigned char payload;

  unsigned short sequence;

  unsigned int timestamp;

  unsigned int ssrc;

  };

  #pragma pack()

  int main(void)

  {

  printf(“%d\n”,sizeof(info_t));

  printf(“%d\n”,sizeof(info_u));

  return 0;

  }A、12 12 B、12 4 C、16 4 D、16 12 E、16 1

  4、以下表达式result的值是()

  #define VAL1(a,b) a*b

  #define VAL2(a,b) a/b–

  #define VAL3(a,b) ++a%b

  int a = 1;

  int b = 2;

  int c = 3;

  int d = 3;

  int e = 5;

  int result = VAL2(a,b)/VAL1(e,b)+VAL3(c,d);

  #define VAL1(a,b) a*b

  #define VAL2(a,b) a/b–

  #define VAL3(a,b) ++a%b

  int a = 1;

  int b = 2;

  int c = 3;

  int d = 3;

  int e = 5;

  int result = VAL2(a,b)/VAL1(e,b)+VAL3(c,d);A、-2 B、1 C、0 D、2

  5、请写出以下程序的输出(5分)

  void swap_1(int a , int b)

  {

  int c;

  c = a;

  a = b;

  b = c;

  return ;

  }

  void swap_2(int &a , int &b)

  {

  int c;

  c = a;

  a = b;

  b = c;

  return ;

  }

  void swap_3(int *a , int *b)

  {

  int c;

  c = *a;

  *a = *b;

  *b = c;

  return ;

  }

  int main(void)

  {

  int a = 100;

  int b = 200;

  swap_1(a , b);

  printf(“a = %d , b = %d\n”,a , b);

  swap_2(a , b);

  printf(“a = %d , b = %d\n”,a , b);

  swap_3(&a , &b);

  printf(“a = %d , b = %d\n”,a , b);

  return 0;

  }

  void swap_1(int a , int b)

  {

  int c;

  c = a;

  a = b;

  b = c;

  return ;

  }

  void swap_2(int &a , int &b)

  {

  int c;

  c = a;

  a = b;

  b = c;

  return ;

  }

  void swap_3(int *a , int *b)

  {

  int c;

  c = *a;

  *a = *b;

  *b = c;

  return ;

  }

  int main(void)

  {

  int a = 100;

  int b = 200;

  swap_1(a , b);

  printf(“a = %d , b = %d\n”,a , b);

  swap_2(a , b);

  printf(“a = %d , b = %d\n”,a , b);

  swap_3(&a , &b);

  printf(“a = %d , b = %d\n”,a , b);

  return 0;

  }输出结果:

  a = 100 , b = 200

  a = 200 , b = 100

  a = 100 , b = 200

  6、下面的程序是否有问题,如有问题,请重构代码(5分)

  void test_type(bool b , const char *p , float f)

  {

  if(!b)

  {

  return ;

  }

  else if(!p)

  {

  return ;

  }

  else if(!f)

  {

  return ;

  }

  }

  void test_type(bool b , const char *p , float f)

  {

  if(!b)

  {

  return ;

  }

  else if(!p)

  {

  return ;

  }

  else if(!f)

  {

  return ;

  }

  }修改如下:

  void test_type(bool b , const char *p , float f)

  {

  if(!b)

  {

  return ;

  }

  else if(!p)

  {

  return ;

  }

  else if(f > -1e-10 && f < 1e-10)

  {

  return ;

  }

  }

  void test_type(bool b , const char *p , float f)

  {

  if(!b)

  {

  return ;

  }

  else if(!p)

  {

  return ;

  }

  else if(f > -1e-10 && f < 1e-10)

  {

  return ;

  }

  }7、请指出以下程序有什么问题(5分)

  void test_mem()

  {

  char *p = new char[64];

  delete p;

  p = NULL;

  return ;

  }

  void test_mem()

  {

  char *p = new char[64];

  delete p;

  p = NULL;

  return ;

  }应该修改为 delete[]p; p指向的`是一个字符型的数组空间,原来的代码只是简单的释放了指向申请空间的指针,并没有释放申请的空间,容易造成内存崩溃,

海康威视校园招聘笔试题

资料共享平台

《海康威视校园招聘笔试题》()。

  回收用 new 分配的单个对象的内存空间的时候用 delete,回收用 new[] 分配的一组对象的内存空间的时候用 delete[]。

未经允许不得转载:全书网 » 海康威视校园招聘笔试题

赞 (0)